When 0.3 m3 /s of water flows through a 150-mm-diameter constriction (B) in a 300-mm-diameter vertical pipeline (A), the pressure at point A in the pipe is 345 kPa, and the head loss between this point (A) and the constriction (B) is 2 m. The pressure in the constriction (B) is 180.3 kPa. How high is the constriction (B) from the point A?

The constriction is 13.94 m high from point A

Step-by-step explanation:

When we apply energy relation between point A and point B, we get:

Pb/ρg + Vb²/2g= Pa/ρg + Va²/2g - Head Loss - h

where,

Pb = Pressure at constriction (B) = 180.3 KPa = 180300 Pa

Vb = Velocity at constriction (B) = (0.3 m³/s)/π(0.15 m)² = 4.24 m/s

Pa = Pressure at  (A) = 345 KPa = 345000 Pa

Va = Velocity at (A) = (0.3 m³/s)/π(0.3 m)² = 1.06 m/s

g = 9.8 m/s²

ρ = density of water = 1000 kg/m³

Head Loss = 2 m

h = Height of constriction = ?

Therefore:

h = (Pa- Pb)/ρg + (Va² - Vb²)/2g - Head Loss

h = (345000 Pa - 180300 Pa)/(1000 kg/m³)(9.8 m/s²) + [(1.06m/s)² - (4.24 m/s)²]/2(9.8 m/s²) - 2 m

h = 16.8 m - 0.86 m - 2 m

h = 13.94 m

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb