Between the time Iko woke up and lunchtime, the temperature rose by 11 degrees. Then, by the time he went to bed, the temperature dropped by 14 degrees. Write an addition expression for the temperature relative to when Iko woke up.

Relative to when Iko woke up, the temperature dropped by 3 degrees.

Step-by-step explanation:

The data that we have is:

Between Iko woke up and the lunchtime, the temperature risen by 11°

If the temperature when Iko woke up is T0, we have that the temperature at the lunchtime hour is T0 + 11°

When he went to bed, the temperature dropped by 14°

So the new temperature is T0 + 11° - 14° = T0 - 3°

The difference between the temperature relative to when Iko woke up is equal to the final temperature minus the temperature when Iko woke up, this is:

T0 - 3° - T0 = -3°

This means that the total change in temperature is equal to -3°

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

3 is greater then both of those numbers