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4) Which step could be completed in order to prepare the system of equations below for the elimination method?

1st Equation: 5x-3y=10
2nd Equation: 8x+6y=15

A Multiply the 1st equation by -2
B Multiply the 2nd equation by 2
C Multiply the 1st equation by 2
D Multiply the 2nd equation by -2

C Multiply the 1st equation by 2

Step-by-step explanation:

-6y + 6y = 0

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

b and c

step-by-step explanation: