"A sample of 30 randomly selected oranges was taken from a large population, and their diameters were measured. The mean diameter of the sample was 91 mm and the standard deviation was 8 mm. Assuming a Normal distribution, calculate (correct to one decimal place) 85% confidence limits for the mean diameter of the whole population of oranges."

The lower bound of the interval is 88.9mm and the upper bound is 93.1mm.

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

So it is z with a pvalue of , so

Now, find M as such

In which is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 91 - 2.1 = 88.9mm.

The upper end of the interval is the sample mean added to M. So it is 91 + 2.1 = 93.1 mm

The lower bound of the interval is 88.9mm and the upper bound is 93.1mm.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

the diver is 33 feet below the surface.

step-by-step explanation:

hope this