1. Given a regular octagon, find the measures of the angles formed by (a) two consecutive radii and (b) a radius and a side of the polygon. a. 40°; 230° b. 45°; 67.5° c. 72°; 252° d. 36°; 216°

(B)45°, 67.5°

Step-by-step explanation:

A regular polygon is a polygon in which all the sides are equal.

An Octagon is a polygon with 8 sides.

Since it is a Regular polygon, the following holds:

1.The Radii are equal

2. The angle Subtended by two radii are equal for all triangles in the octagon.

3. There are 8 Isosceles triangles in the octagon.

(a)Measures of angle formed by Two radii

From the centre of the octagon, there are 8 equal angles.

Sum of Angle at a point= 360°

Each Angle=360°÷ 8 = 45°

The measures of angle formed by two radii is 45°.

(b)a radius and a side of the polygon.

Since the triangles are Isosceles, the base angles at the side of the octagon are equal.

Let x be the angle made by a radius with a side.

From (a) above,

x+x+45°=180°(Sum of Angle in a Triangle)

2x=180-45°

2x=135°

x=135°÷2=67.5°

The angle between a radius and a side of the polygon is 67.5°.

a

b

d

step-by-step explanation:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~