The probability that a person will have 0, 1, or 2 dental checkups per year is 0.3, 0.6, and 0.1, respectively. If seven people are picked at random, what is the probability that two will have no checkups, four will have one checkup, and one will have two checkups in the next year?
A) 0.012
B) 0.122
C) 0.588
D) 0.018

Step-by-step explanation:

Here, given:

The probability of having 0 dental checkup = 0.3

The probability of having 1 dental checkup = 0.6

The probability of having 2 dental checkup = 0.1

Number of people chosen at random  = 7

So, the number of ways 2, 4 and 1 checkup are :  

Now, the combined probability  that two will have no checkups, four will have one checkup, and one will have two checkups in the next year

=

Hence, the required probability is 0.1224.

78.59 is the mean

step-by-step explanation:

with btw u said 100pts but it clearly says

i answerd and just got 10pts

no hate