Solve for y: 2y + 3 =11

Solve for x:
2/3x = 18

y=4 x=27

Step-by-step explanation: 2y+3=11

-3 -3

2y=8

/2 /2

y=4

2/3x=18

(3) (3)

2x=54

/2 /2

X=27

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180