Can someone help please ❤️❤️

(A) The mean is 82

(B) The mean absolute deviation is approximately 9.71

(D) The IQR is 11

Explanation:

(A) 89, 87, 54, 78, 87, 99, 80

Mean of the data =

Therefore, mean of the data is 82

(B) The mean absolute deviation, MAD is

data - 54, 78, 80, 87, 87, 89, 99

Mean of the data, x' is 82

|x - x'| : 54 - 82 = 28

           78 - 82 = 4

           80 - 82 = 2

           87 - 82 = 5

           87 - 82 = 5

           89 - 82 = 7

           99 - 82 = 17

Total of |x - x'| = 68

MAD = |x - x'| / n

MAD = 68/7

MAD = 9.71

(D) IQR is the interquartile range

Data = 54, 78, 80, 87, 87, 89, 99

IQR = median of lower quartile range - median of upper quartile range

IQR = 89 - 78

IQR = 11

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

hit or miss i guess they never miss huh

step-by-step explanation:

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