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Mathematics, 24.03.2020 10:44 H7ttaMaan

Given the equation of the parabola: -36y = x^2

The focus of the parabola is:

A. (0, -9)
B. (-9, 0)
C. (0, 9)

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Answers: 2

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Given the equation of the parabola: -36y = x^2

The focus of the parabola is:

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