Which statement is true about the discontinuities of the function f(x)?

f (x) = StartFraction x + 1 Over 6 x squared minus 7 x minus 3 EndFraction
There are asymptotes at x = three-halves and x = negative one-third.
There are holes at x = three-halves and x = negative one-third.
There are asymptotes at x = negative three-halves and x = one-third.
There are holes at x = negative three-halves and x = one-third.

Using the discontinuity concept, it is found that:

There are asymptotes at and

------------------------------------

A function is discontinuous at a point outside it's domain, and at these points in the graph there will be asymptotes.

------------------------------------

The given function is:

It is a fraction, then the denominator cannot be zero, and the asymptotes will be at the values of x for which:

------------------------------------

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

.

This polynomial has roots such that , given by the following formulas:

------------------------------------

For this equation, . Thus:

Thus, there are asymptotes at and

The graph of the function is given at the end of the answer.

A similar problem is given at link

d i think

step-by-step explanation:

55% are girls and 45% are boys : ) hope this

step-by-step explanation: