An observation deck extends 120 feet out above a valley. The deck sits 70 feet above the valley floor. If an object is dropped from the observation deck, its height h in feet, after t seconds, is given by h equals negative 16 t squared plus 70. How long will it take for the object to be 6 feet above the valley floor? It will take seconds for the object to be 6 feet above the valley floor.

2

Step-by-step explanation:

The height formula given is:

h = -16t^2 + 70

That means the object will be initially (t=0) at the height 70 feet, from where it will be dropped.

If we want to know the time when the object will be at height 6 feet, we just need to use h=6 in the equation, and then calculate the value of t:

6 = -16t^2 + 70

16t^2 = 64

t^2 =4

t = 2 s

So, it will take 2 seconds for the object to be 6 feet above the valley floor.

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !

the square root of what number? if you add that, then someone will probably answer the question.