Mr. Parker is graphing a quadrilateral. He wants the quadrilateral to be a trapezoid. He has already graphed vertices at (1, 1), (3,
3), and (5, 3). Which choice is a point that could be the 4th vertex?

A trapezoid is a quadrilateral where at least one pair of opposite sides are parallel. Here Mr. Parker is graphing a quadrilateral, so he wants the quadrilateral to be a trapezoid. He has already graphed vertices at:

So these points have been plotted below. As you can see form the graph, points (3, 3) and (5, 3) has the same y-coordinates, so the line that passes through these two points has zero slope. The other point is (1, 1) so we can choose any point such that the slope of the the line that passes through (1, 1) and that point also has zero slope. Therefore, the 4th vertex is any point of this form:

25% is the answer

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.