F(n)=5 (2)^n-1 identify the first five terms if f(1) is the first term?

The first five terms are: 5,10,20,40,80

Step-by-step explanation:

The given sequence is defined explicitly as:

We want to find the first five terms of this sequence:

For the first term, n=1,

When n=2,

When n=3,

We have

When n=4, we get:

When n=5,

The first five terms are: 5,10,20,40,80

heudhduxhdnshenebdutbbt

step-by-step explanation:

hrhhdhdbbrurb ees

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.