Please help me with this problem, thank you.

The answer is just 117.

Every straight line is 180 degrees, meaning that the angle of ∠ABE and ∠CBE must add up to 180. You can say that ∠ABE + ∠CBE = 180. If you rearrange, you can see that ∠ABE = 180 - ∠CBE. Since ∠CBE is given as 63, all you need to do is subtract this from 180 to get 117.

Hope this helps!

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.