A card is chosen at random from a deck of 52 cards. It is then replaced and a second card is chosen. What is the probability of choosing a Jack and then a 3?

1/169.

Step-by-step explanation:

Prob(Choosing a Jack on the first draw) = 4/52 = 1/13.

Prob(Choosing a 3 on the second draw) = 4/52 = 1/13.

Required probability  = 1/13 * 1/13 = 1/169.

y=mx+

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

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