What is the smallest integer greater than 1 that leaves a remainder of 1 when divided by any of the integers 6,8 and 10?

It leaves a remainder of 3
that means is it NOT a multipule of 6 or 8 or 10
it has to be more than 10 though
6x+1=8y+1=10z+1
subtract 1 from everybody
6x=8y=10z
so basically what is the least common multplule and then add 1
LCM

factor
6=2*3
8=2*2*2
10=2*5
therefor the LCM=2*2*2*3*5=120
then add 1
120+1=121

the smallest intege is 121

I’m sure you could google it. my profile picture might