Solve the following system of equations: y=6-x
y=x^2-6x+6

(0, 6 ) and (5, 1 )

Step-by-step explanation:

Given the 2 equations

y = 6 - x → (1)

y = x² - 6x + 6 → (2)

Substitute y = x² - 6x + 6 into (1)

x² - 6x + 6 = 6 - x ( subtract 6 - x from both sides )

x² - 5x = 0 ← factor out x from each term on the left side

x(x - 5) = 0

Equate each factor to zero and solve for x

x = 0

x - 5 = 0 ⇒ x = 5

Substitute these values into (1) for corresponding value of y

x = 0 : y = 6 - 0 = 6 ⇒ (0, 6 )

x = 5 : y = 6 - 5 = 1 ⇒ (5, 1 )

2nd one in the first row is correct

answer:  

step-by-step explanation:

odd numbers are only divisible by 1 and itself.

even numbers are divisible by more than 1 and itself.

for example 6 is even because it is divisible by more than 1 and its self. 1 x 6= 6 ; 2 x 3= 6

and 7 is odd because only 7 x 1 equals seveb