The plastic arrow on a spinner for a child's game stops rotating to point at a color that will determine what happens next. Are the given probability assignments possible? Red Yellow Green Blue a) 0.3 0.3 0.3 0.3 b) 0.1 0.2 0.3 0.4 c) 0.25 025 0.25 0.25 d) 0. 5 0.3 0.5 -0.3

Assignment 2, 3 and 4 are possible.

Step-by-step explanation:

We are given the following probability assignments below;

               Red        Yellow        Green       Blue

          1.)    0.3           0.3             0.3           0.3

         2.)     0.1            0.2             0.3           0.4

         3.)    0.25         0.25          0.25         0.25

         4.)     0.5           0.3             0.5          -0.3

Now, as we know that the Sum of all probabilities is equal to 1.

So, we will add the probabilities the all these four assignments to identify that which of these is possible separately.

Assignment 1 :

                     Red        Yellow        Green       Blue

                      0.3           0.3             0.3           0.3

Sum of all these four probabilities = 0.3 + 0.3 + 0.3 + 0.3 = 1.2

Since, the sum is not equal to 1 so this assignment is not possible.

Assignment 2 :

                     Red        Yellow        Green       Blue

                      0.1            0.2             0.3           0.4

Sum of all these four probabilities = 0.1 + 0.2 + 0.3 + 0.4 = 1

Since, the sum is equal to 1 so this assignment is possible.

Assignment 3 :

                     Red        Yellow        Green       Blue

                     0.25         0.25           0.25         0.25

Sum of all these four probabilities = 0.25 + 0.25 + 0.25 + 0.25 = 1

Since, the sum is equal to 1 so this assignment is possible.

Assignment 4 :

                     Red        Yellow        Green       Blue

                      0.5            0.3             0.5          -0.3

Sum of all these four probabilities = 0.5 + 0.3 + 0.5 + (-0.3) = 1

Since, the sum is equal to 1 so this assignment is possible.

Therefore, Assignment 2, 3 and 4 are possible.

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

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