Captain Tiffany has a ship, the H. M.S. Khan. The ship is two furlongs from the dread pirate Omar and his merciless band of thieves. The Captain has probability of 1/2 of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability 2/7.If both fire their cannons at the same time, what is the probability that both the pirate and the Captain hit each other's ships

0.1428 is the probability that both the pirate and the Captain hit each other's ships.

Step-by-step explanation:

We are given the following in the question:

Probability of captain hitting pirate's ship =

Probability of pirate hitting captain's ship =

If events are independent events, we can write:

We have to evaluate the probability that both the pirate and the Captain hit each other's ships.

0.1428 is the probability that both the pirate and the Captain hit each other's ships.

The answer is 1/7

Step-by-step explanation:

answer: re

step-by-step explanation: idk buddy

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2