Question 3 (1 point)
Complete the square to put the circle in standard form:
x2 + y2 - 4x + 12y – 7 = 0
O (2 + 2)2 + (y – 6)= 47
© (x – 5)+ (y + 2) = 147
O (2 – 2)² + (y + 6)2 = 47
(2 – 6)2 + (x - 2)² = 47