The difference of the squares of two positive consecutive even integers is 68 Find the integers Use the fact that, if x represents an even integer then x + 2 represents
the next consecutive even integer

different of two squares states that

If a²-b² is given then

a²-b²=(a+b)(a-b)

Now to answer the question

(x+2)²-(x)²=68

(x+2+x)((x+2)-x)=68

(2x+2)(x+2-x)=68

(2x+2)(2)=68

Divide both sides by 2

{(2x+2)(2)}÷ 2 = 68/2

2x+2= 34

Collect like terms

2x=34-2

2x=32

Divide both sides by 2

2x/2 =32/2

x=16

Hence

x=16

x+2=16+2=18

The two consecutive even integer are 16 and 18

Step-by-step explanation:

what is the question?

step-by-step explanation:

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.