V1 = 70 mL; P1 = ? kPa; P2 = 105 kPa; V2 = 15 mL *

490kpa

Step-by-step explanation:

V1 = 70ml and P1 = ? kpa

V2 = 15ml and P2 = 105kpa

if 15ml will give me 105kpa

then how many times is 70ml greater than 15ml

70/15 = 4.6667

then multiply it by 105kpa

4.6667 * 105 = 490kpa

meaning that if 15ml will give me 105kpa

then 70ml which is (15*4.667) will give 490kpa

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)