Anyone able to help with this question?

This is trigonomentry

Use SOHCAHTOA

where :

s is sin

c is cos

t is tan

o is opposite (side)

h is hypotenuse (opposite of 90 degree angle)

and a is adjacent (side)

Sin = o/h

cos = a/h

tan = o/a

in this case we are looking for side BC which is the hypotenuse(h)

and we have the side adjacent(a) to angle 71

since we have a and h determine what to use SIN, COS, OR TAN?

we should use Cos

they‘ve given the angle so we should do this...

Cos71 =

Cos71 =

now apply algebra...

6.3/cos71= BC

BC= 19.3507869666

BC = 19.4   (3SF)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

c

step-by-step explanation: