Allysa spent $35 to purchase 12 chickens. She bought two different types of chickens. Americana
chickens cost $3.75 each and Delaware chickens cost $2.50 each.
Write a system of equations that can be used to determine the number of Americana chickens, A,
and the number of Delaware chickens, D, she purchased.
Determine algebraically how many of each type of chicken Allysa purchased.

Allysa purchased 4 Americana chickens and 8 Delaware chickens✔️

Step-by-step explanation:

From the information they provide us, we have to establish the necessary equations to solve the problem.

Let A be the American chickens and D be the Delaware chickens.

Allysa purchased 12 chickens:

A + D = 12 } Equation 1

Americana chickens cost $3.75 each and Delaware chickens cost $2.50 each. Allysa spent $35:

$3.75A + $2.50D = $35 } Equation 2

We take the value of A from equation 1 and substitute it into equation 2:

A = 12 - D } Equation 1  

$3.75A + $2.50D = $35 } Equation 2

$3.75(12 - D) + $2.50D = $35

$3.75·12 - $3.75D + $2.50D = $35

$45 -$3.75D + $2.50D = $35

$45 - $35 = $3.75D - $2.50D

$10 = $1.25D

D = $10/$1.25 = 8 , Delaware chickens  

A = 12 - D = 12 - 8 = 4 , Americana chickens

Allysa purchased 4 Americana chickens and 8 Delaware chickens✔️

We can substitute these values in the equation 2

$3.75A + $2.50D = $35 } Equation 2

$3.75·4 + $2.50·8 = $15 + $20 = $35 ✔️Checked!

is there any photos or whatever?

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)