Whats the formula of the sequence 13, 27, 41, 55, ?
A. a^n = 13 + 14(n-1) B. a^n = 13(n-1) C. a^n = 13(14)^(n-1)
D. a^n = 14 + 13(n-1)

A

Step-by-step explanation:

Note the common difference between consecutive terms in the sequence.

d = 27 - 13 = 41 - 27 = 55 - 41 = 14

This indicates the sequence is arithmetic with n th term

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 13 and d = 14, thus

= 13 + 14(n - 1) → A

the answer to this question is yes

step-by-step explanation:

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