The opposition to current in an electrical circuit is called its impedance. the impedance z in a parallel circuit with two pathways satisfies the equation: 1/z + 1/z1 + 1/z2 where z1 is the impedance (in ohms) of pathway 1 and z2 is the impedance of pathway 2.
a) the impedance of each pathway in a parallel circuit is found by adding the impedances of all components in the pathway. use the table to find z1 and z2.
b) find the impedance z.
(diagram drawn)

a 1/z1 = 1/bi

 1/z2 = -1/ci

b impedance z = 1/z = [(1/a)² + (-1/ci -1/bi)²]^1/2

Step-by-step explanation:

circuit in parallel

a for the resistor impedance  = 1/z = 1/ a

for the inductor inductance   = 1/ bi = 1/xL

for the capacitor capacitance  = - 1/ci = 1/xc

the reactances  is the INDUCTANCE AND CAPACITANCE

The impedance = 1/z = [ (-1/ci -1/bi)²]^1/2

Since the circuit is parallel impedance z across the pathway is given by

b impedance z = 1/z = [(1/a)² + (-1/ci -1/bi)²]^1/2

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

3 is greater then both of those numbers