2. Triangle XYZ has vertices X(-1, -2), Y(6, -3) and Z(2,-5).
Find the vertices of AXY'Z' after a translation of 2 units left
and 1 unit up.
Use a table. Add 2 to the x-coordinates and 1 to the
y-coordinates.
Vertices of
Η ΔΧΥΣ
i
Vertices of
(ΚΕΕ2)
Υ ΔΧΥΖΗ
X(-1, -2) (-1+(-2), –2 + 1) | X(-3,-1)
Y(6,-3) (6 +(-2), -3 + 1) Y(4,-2)
Z(2,-5) (2+(-2), -5 + 1) z'(0, –4)
So, the vertices of AX'Y'Z' are X'(-3, -1), Y'(4, -2), and Z'(0, –4).

40% off the regular price is the correct answer.

step-by-step explanation:

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy

113.1

step-by-step explanation:

v=4

3πr3=4

3·π·33≈113.09734