Angie and Becky each completed a separate proof to show that the measures of vertical angles AKG and HKB are equal. Who completed the proof incorrectly? Explain.

line AB intersecting line GH at K

Angie's Proof

Statement Justification

1. Segment GH intersects segment AB at K 1. Given

2. m∠AKG + m∠GKB = 180°

m∠GKB + m∠HKB = 180° 2. Definition of Supplementary Angles

3. m∠AKG + m∠ GKB = m∠GKB + m∠HKB 3. Substitution Property

4. m∠AKG = m∠HKB 4. Subtraction Property

Becky's Proof

Statement Justification

1. Segment GH intersects segment AB at K 1. Given

2. m∠AKG + m∠GKB = 180°

m∠GKB + m∠HKB = 180° 2. Angle Addition Postulate

3. m∠AKG + m∠ GKB = m∠GKB + m∠HKB 3. Substitution Property

4. m∠AKG = m∠HKB 4. Subtraction Property

what?

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.