Solve the system by elimination 2x - 2y = 6 and 3x + 2y = 9

X=3,y=0

Step-by-step explanation:

This is elimination method which is under the topic simultaneous equation

2x-2y=6...(1)

3x+2y=9...(2)

Add (1) and (2)

It gives

5x=15

Make x the subject of formula by dividing both sides by 5

x=3

Let's substitute the value of x in (2)

3(3)+2y=9

9+2y=9

Collect like terms

2y=9-9

2y=0

y=0

Therefore x is 3,y is 0

(3,0)

Step-by-step explanation:

2x - 2y = 6

3x + 2y = 9

We are using elimination.  Add the two equations together to eliminate y

2x - 2y = 6

3x + 2y = 9

5x +0   = 15

5x=15

Divide each term by 5

5x/5 = 15/5

x = 3

Now we need to find y

3x+2y =9

3(3) +2y = 9

9+2y =9

Subtract 9 from each side

9-9 +2y =9-9

2y =0

Divide each side by 2

2y/2=0/2

y=0

first, let's see what the pattern is.

58 - x = 47

46 - x = 36

x = 9

so this means that the term after 25 is 25 - 9:

the next term in the sequence is 16.