Please help, it's urgent!

If sin y° = 7 over q and tan y° = 7 over r, what is the value of sec y°?

A: sec y° = q/r
B: sec y° = 7r
C: sec y° = 7q
D: sec y° = r/q

sec y° is q/r

Step-by-step explanation:

Using sin y = opposite side/hypotenuse = 7/q

⇒ opposite side = 7 and hypotenuse = q

Using tan y = opposite side/adjacent side = 7/r

⇒ adjacent side = r

sec y = hypotenuse/adjacent side = q/r

took the test it's 94

can i get the link to the assignment?

step-by-step explanation: