If one zero of polynomial 2x^3+x^2-7x-6 is 2 then find all zeroes

2,-1 and -3/2

Step-by-step explanation:

If one zero of polynom is 2 then we can divide our polinom with (x-2), and we will get

(2x^3+x^2-7x-6)/(x-2)=2x^2+5x+3

Now we have ti find zeros for 2x^2+5x+3

3 is without x so we have factors:

1,-1,3,-3, 1/2,-1/2,3/2,-3/2.

Chack does any of them zero.

For -1 we have:

2(-1)^2+5(-1)+3=2-5+3=0

So -1 is zero of the polynom.

Now divide again with (x+1) wi get:

(2x^2+5x+3)/(x+1)=2x+3

2x+3=0 if x=-3/2

So we have all zeros:

2,-1 and -3/2

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it

i think the answer is fried chicken ; >

step-by-step explanation: