Please help me with these algebra questions. Image attached.

Question 4:

m = 4 or -2

Question 5:

a = 5

b = -3

c= -19

Step-by-step explanation:

1. TO PERFORM COMPLETING THE SQUARE PROCESS, the 1st thing i will do is to reduce the coefficient of x^2 to be 1. Then, I'll transfer the constant C to the right hand side of the equation, after that I'll square half the coefficient of x and then solve on from there.

2. Since the coefficient of m^2 is 1. I'll just add the square of half the coefficient of m to both sides. That is, I'll add up -9 to both sides of the equation.

3. I will make the coefficient of m^2 to be one. That is, I'll divide through the equation by 4.

4. 4m^2 - 8m = 32

Divide through by 4

m^2 - 8m/4 = 32/4

m^2 -2m = 8

Add the Square of half the coefficient of m to both sides

m^2 -2m + (-2/2)^2 = 8+ (-2/2)^2

Factorizing, we then have:

(m - 1)^2 = 9

Take the Square roots of both sides:

m - 1 = √9

m - 1 = plus or minus 3

m = 1 + 3

m = 4.

OR

m = 1-3

m = -2.

Therefore, m = 4 or -2

5. From the equation:

5x^2 -19 = 3x

5x^2 -3x - 19 = 0

a = 5

b = -3

c= -19

Math is fun

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

probably .5

i can on others if necessary.