Andrew starts walking at noon at a speed of 3 miles per hour. Christian leaves the same place an hour later and walks in the same direction at a speed of 4 miles per hour. What time will Christian catch up with Andrew?

Christian will catch up with Andrew at 4 PM.

Step-by-step explanation:

We use the equations of their positions to solve this question. This equation has the following format:

In which S(t) is the position after t hours, S(0) is the initial position, and a is their speed.

Andrew starts walking at noon, Christian at 1.

We can model the equations starting from 1.

Andrew:

Starts at noon, 3 mph.

So at 1, when Christian starts walking, he is at the mile 3. So S(0) = 3. 3mph, a = 3. So

Christian:

Starts at 1, 4 mph.

So at 1, he is at the position 0. So S(0) = 0. 4 mph, so a = 4.

What time will Christian catch up with Andrew?

t hours after Christian starts walking(which is 1 pm).

t is found when

3 hours after 1 PM, which is 4PM.

Christian will catch up with Andrew at 4 PM.

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign