Let S be a set of ordered pairs of integers defined recursively by (a) Base step: (0,0) is element of S (b) Recursive step: If (a, b) is element of S, then (a 4, b 3) is element of S and (a 2, b 5) element of S. Use structural induction to show that a b is divisbile by 7 for any (a, b) is element of S

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

think about it deeply and passionately about this property

i am sorry

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

happy to

pls mark as brainliest

too many. (jk)

31 v bucks

step-by-step explanation:

since you bought 25 on friday and 6 on tuesday, you can just add them up.

25+6=31

check your work.

31-6=25

i hope this !

-yand3r3