Find a vector equation of the line through (11,55,66) that is perpendicular to the lines R1(t)=<2-2t,2+9t,5-3t>2-2t,2+ 9t,5-3t and R2(t)=<-2t,2+t,5-t, where t=0 corresponds to the first given point

I don't know what the answer is I wish I could help

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.