9) In a survey of college students, 871 said that they have cheated on an exam and 1756 said that they have not. If one college student is selected at random, find the probability that the student has cheated on an exam. A) 2627 1756 B) 871 2627 C) 2627 871 D) 1756 2627

Step-by-step explanation:

Given that "In a survey of college students, 871 said that they have cheated on an exam and 1756 said that they have not.

Let x be the number of students cheated on an exam

Therefore x=871 students

Let y be the number of students not cheated in exam

Therefore y=1756 students

Total number of students is 871+1756

Total number of college students = 2627

Now the probability that the student has cheated on an exam, if one college student is selected at random  is given by

Therefore

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;