According to the National Postsecondary Student Aid Study conducted by the U. S. Department of Education in 2008, 62% of graduates from public universities had student loans. We randomly select 50 students at a time. Flag this Question Question 15 pts What is the mean of the distribution of sampling proportions? Do not round, and enter your answer as a proportion (decimal number) not a percentage. Flag this Question Question 25 pts What is the standard error for the distribution of sampling proportions? If necessary, round to three decimal places.

The mean of the sampling proportions is 0.62.

The standard error for the distribution of sampling proportions is 0.069.

Step-by-step explanation:

The proportion of graduates from public universities that had student loans is p=0.62.

The sampling distribution of the proportions, if the sample are of size n=50, has the following parameters:

The mean of the sampling proportions is 0.62.

The standard error for the distribution of sampling proportions is 0.069.

50

step-by-step explanation:

55.44 inches

step-by-step explanation:

part a. assuming a perfectly linear relationship, we can find the slope from the first two data points.

slope = m = (change in rainfall)/(change in years)

= (61.80 -62.33)/(2005 -2004) = -0.53/1 = -0.53

then the point-slope form of the equation of the line can be written as

y = m(x -h) +k . . . . . m = -0.53, (h, k) = (0, 62.33)

y = -0.53x +62.33 . . . x = years after 2004

part b. in 2017, x = 2017 -2004 = 13. then the predicted rainfall is

y = -0.53·13 +62.33 = 55.44 . . inches

the predicted rainfall in 2017 is 55.44 in.