The area of a circle of radius r is given by A=\pi r^2A=πr 2 and its circumference is given by C=2\pi rC=2πr. At a certain point in time, the radius of the circle is r=8r=8 inches and the area of the circle is changing at a rate of \frac{dY}{dt}=\pi\sqrt{2} dt dA =π 2 square inches per second. How fast is the radius of the circle changing at this time

Step-by-step explanation:

If I'm understanding this correctly, your problem is as follows:

The area of a circle is given by the formula

The area of the circle is changing at a rate of .  Find the rate of change of the radius, , when r = 8.

Assuming that is what you are asking, we will begin by finding the derivative of the area of a circle using implicit differentiation.

Filling in what we have:

which simplifies a bit to

Divide both sides by 16π to get:

The π's cancel leaving the rate of change of the radius as

inches per second

answer: there are x+184 pages in olivia's book.

step-by-step explanation:

let the total number of pages in the book which olive has already read be x.

then if olive has 184 pages left to read, then the total number of pages are in olive's book= pages she has read+pages she has left to read

therefore, the total number of pages in olivia's book=

hence, there are x+184 pages in olivia's book.

x equals 1

step-by-step explanation:

f(4)=f(×)

x=1