Adult tickets to a play cost $22.00 Tickets for children cost $15.00. Tickets for a group of 11 people cost a total of $228.00. Write and solve a system of equations to find how many children and how many adults were in the group.

Here is the set up:

Let x represent the number of adults
Let y represent the number of children

x + y = 11 (only 11 people were in the group )
22x + 15y = 228 ( This is the equation that deals with money )

Now you finish it.

Show work:

The number of children is

The number of adults is

The answer to your question is 9 adults and 2 children

Step-by-step explanation:

Data

adult ticket = $22

children ticket = $15

Total people= 11

total cost = $228

Number of adults = x = ?

Number of children = y = ?

Process

1.- Write equation to solve the problem

              x + y = 11                           Equation l

           22x + 15y = 228                  Equation ll

-Solve Equation l by x

              x = 11 - y                            Equation lll

-Substitute equation lll in equation ll

          22(11 - y) + 15y = 228

-Solve for y

         242 - 22y + 15y = 228

-Simplify like terms

                -7y = 228 - 242

                -7y = -14

                   y = -14/-7

                  y = 2

-Find x

              x = 11 - 2

              x = 9

2.- Conclusion

There were 9 adults and 2 children.                

is there answer choices?

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4