I need some help please

x^2(4+3x)

4x^2+3x^3

Step-by-step explanation:

hope this helps you

x=-3/4,x=0

Step-by-step explanation:

The question is x^2(4+3x)

So to solve we will have to open the bracket

4x^2+3x

Let's equate the equation to zero

4x^2+3x=0

Let's factorise

x(4x+3)=0

x=0

4x+3=0

Substrate both sides by 3

4x=-3

Divide both sides by 4

x=-3/4

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

answer: 0.1,0.85

step-by-step explanation: