George and Riley are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges. George sold 3 small boxes of oranges and 14 large boxes of oranges for a total of $203. Riley sold 11 small boxes of oranges and 11 large boxes of oranges for a total of $220. Find the cost of each of one small box or oranges and one large box of oranges.

The cost of small box of oranges is $7.

The cost of large box of oranges is $13.

Step-by-step explanation:

It is given that,

3 small boxes of oranges and 14 large boxes of oranges for a total of $203.

11 small boxes of oranges and 11 large boxes of oranges for a total of $220.

Let us take,

The system of equations are framed as :

3x + 14y = 203  (1)

11x + 11y = 220  (2)

To solve these equations for x and y values :

Multiply equation (1) by 11 and equation (2) by 3

Subtract eq(2) from eq(1),

 33x + 154y = 2233

- (33x + 33y = 660)  

         121 y = 1573  

⇒ y = 1573 / 121

⇒ y = 13

∴ The cost of large box of oranges is $13.

Substitute y=13 in the eq(1),

⇒ 3x + 14(13) = 203

⇒ 3x + 182 = 203

⇒ 3x = 203 - 182

⇒ 3x = 21

⇒ x = 21 / 3

⇒ x = 7

∴ The cost of small box of oranges is $7.

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches