1. Two object accumulated a charge of
4.5 pc and another a charge of 2.8
PC. These two objects are separated
by a distance of 2.5 cm. Calculate the
magnitude of the electric force
between these two objects.

The  magnitude of the electric force  between these two objects

will be: 181.274 N.

i.e.  F   N

Step-by-step explanation:

As

Two object accumulated a charge of  4.5 μC and another a charge of 2.8  μC.

so

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8  μC = 2.8 × 10⁻⁶  C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

           ∵

       ∵

         ∵

         ∵

F   N

Therefore, the  magnitude of the electric force  between these two objects will be: 181.274 N.

i.e.  F   N

2