Use the quadratic formula to find both solutions to the quadratic equation given below x^2-x+1/4=0

{1/2, 1/2}

Step-by-step explanation:

Eliminating the fraction 1/4 would make this work a little easier:

4x^2 - 4x + 1 = 0.  This is in standard form.  Then a = 4, b = -4 and c = 1.

The discriminant is therefore b^2 - 4ac, or 16 - 4(4)(1), or 0.

Since the discriminant is zero, there are two equal real roots:

      -b ± √(discriminant)

x =

                 2a

which here has the following values:

       4 ± √0

x = , which has two values:  {1/2, 1/2}

           2(4)

seems like d

step-by-step explanation: