Find midpoint between a(3,-3) and b(-3,6)

The answer to your question is midpoint =  (0, 3/2)

Step-by-step explanation:

Data

A (3, -3)

B (-3, 6)

Formula

Xm = (x1 + x2) / 2

Ym = (y1 + y2) / 2

Process

1.- Identify x1, x2, y1 and y2

x1 = 3        y1 = -3

x2 = -3      y2 = 6

2.- Substitution

Xm = (3 - 3)/2

Ym = (6 - 3)/2

3.- Simplification

Xm = 0/2

Ym = 3/2

4.- Result

Xm = 0

Ym = 3/2

or   (0, 3/2)

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2