If BC = 9, AB = 6, and AC = 15, is BC tangent to Circle A?

no

Step-by-step explanation:

because to make BC a tangent, it would have to be perpendicular to BA. so triangle ABC would have to be a right triangle. For this we can use the Pythagorean theorem.

117 does not equal 225, so therefor is is not a right triangle, nor perpendicular

13

step-by-step explanation:

distance formula is d=√(x2-x1)^2   +   (y2-y1)^2

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form