A pair of factors of -35 that has a sum of -2

The pair of factors in question are x = 5 and y = -7

Step-by-step explanation:

Let the factors be represented by x and y.  Then x*y = -35 and x + y = -2.

Solving the first equation for y yields x = -35/y.

Substituting -35/y for x in the second equation yields

-35/y + y = -2.

Multiplying all three terms by y yields -35 + y^2 = -2y, or

y^2 + 2y - 35 = 0.  

Let's solve for y.  Note that this quadratic factors easily into (y + 7)(y - 5) = 0.

Then either y = -7 or y = 5.  Going back to x = -35/y and letting y = -7, we find that x = -35/(-7) = 5.

The pair of factors in question are x = 5 and y = -7, or y = -5 and x = 7.

-7,5

Step-by-step explanation:

lets take x and y as the unknown numbers

xy=-35

x+y=-2

go through all the factors of -35

constants mean the stopped points or the points on a graph that nothing is changing, hope this

step-by-step explanation:

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.