What’s the equation for a line passing through points (-2,-2) and (2,-4)?

y = (-1/2)x - 3  (Answer D)

Step-by-step explanation:

As we move from the point (-2, -2) to the point (2, -4), we see that x increases by 4.  This is the "run.'  At the same time, y decreases by 2.  This is the "rise."  Therefore, the slope is m = rise / run = -2/4, or -1/2.

All of the possible answers are in slope-intercept form, so at this point we start with the appropriate equation y = mx + b.

Using the point (2, -4), we get:          -4 = (-1/2)(2) + b, or

-4 = -1 + b.  Then b = -3, and the desired equation is y = (-1/2)x - 3  (Answer D)

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: