Question 2 (1 point)
Scientists studied the population of a species of bat in some caves in Missouri from
1983 to 2003. In 1983, there were 141,200 bats living in the caves. That number
decreased by about 11% annually until 2003.
How many bats were there in 2000?
O A) 13,729 bats
OB) 19,474 bats
OC) 58,210 bats
OD) 62,455 bats

B) 19474 bats

Step-by-step explanation:

Initial population of bats = 141200

Decrease rate = 11% annually

Time passed until the year 2000 = 2000 -1983= 17 years

Bats population in 2000:

Correct answers choice is: B) 19474 bats

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15