How do you multiply the expression (3x+2)(4x-7)

You "FOIL" (First, Outer, Inner, Last).

Step-by-step explanation:

You "FOIL" (First, Outer, Inner, Last). Basically, you have to multiple each term by each of the other terms.

(3x+2)(4x-7)

(3x)(4x) + (17)(3x) + (2)(4x) + (2)(-7)

12x^2 - 21x + 8x - 14

12x^2 - 13x - 14

12x² - 13x - 14

Step-by-step explanation:

 (3x+2)(4x-7)

Multiply  3x by 4x - 7 and +2 by 4x - 7. That is

3x ( 4x -7) + 2 ( 4x - 7)

(3x × 4x)  - (3x × 7 ) + (2× 4x) - (2×7)

= 12x²  - 21x + 8x - 14

Note : -21x + 8x = -13x.

Therefore

= 12x² - 13x - 14

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x + 4/7

step-by-step explanation:

use cymath

well what did you do it matters what you did : )

step-by-step explanation: