Please help
In Δ XYZ , side Y = 18, m < Y= 39* and m < Z = 51*. Find side Z to the nearest tenth of an integer.

22.2

Step-by-step explanation:

z/sinZ = y/siny

z/sin(51) = 18/sin(39)

z = sin(51) × 18/sin(39)

z = 22.22814882

z = 22.2

Step-by-step explanation:

Considering the given triangle XYZ, to determine side g, we would apply the sine rule. It is expressed as

a/SinA = b/SinB = c/SinC

Where a, b and c are the length of each side of the triangle and angle A, Angle B and angle C are the corresponding angles of the triangle. Likening it to the given triangle, the expression becomes

x/SinX = y/SinY = z/SinZ

Therefore

18/Sin 39 = z/Sin 51

Cross multiplying, it becomes

zSin39 = 18Sin51

0.629z = 18 × 0.777

0.629z = 13.986

z = 13.986/0.629

z = 22.2

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: